Find the equation of the line with m=3, containing (2,3) |
Let's do this problem: m=3, containing (2,3) In other words, you need to find the line with slope m=3 that goes through the point (2,3) A line in slope-intercept form looks like y=mx+b But you know m=3 so your line looks like y=3x+b Let's find b by plugging in (2,3) for (x,y) (3)=3(2)+b b=-3 So the line is y=3x-3 (You got this one right) Here's a graph that shows that y=3x-3 is the line that has slope 3 and goes through (2,3) y=3x-3, (2,3) |
No I know I got that one right I just need help with the one that says (-3,1) AND (5,4) |