Find the equation of the line with m=3, containing (2,3)


Let's do this problem:

m=3, containing (2,3)

In other words, you need to find the line with slope m=3 that goes through the point (2,3)

A line in slope-intercept form looks like

y=mx+b

But you know m=3 so your line looks like

y=3x+b

Let's find b by plugging in (2,3) for (x,y)

(3)=3(2)+b

b=-3

So the line is y=3x-3

(You got this one right)

Here's a graph that shows that y=3x-3 is the line that has slope 3 and goes through (2,3)

y=3x-3, (2,3)

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No I know I got that one right I just need help with the one that says (-3,1) AND (5,4)

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