Here's my problem: a/(2a-6) - 3/(a^2-6a+9) = (a-2)/(3a-9) TIA, Zameaze |
a/(2a-6) - 3/(a^2-6a+9) = (a-2)/(3a-9) a/(2(a-3)) -3/((a-3)(a-3)) = (a-2)/(3(a-3)) multiply all terms by (a-3) a/2 - 3/(a-3) = (a-2)/3 multiply by 6(a-3) 3a(a-3) -3*6=2(a-2)(a-3) 3a^2-9a-18=2a^2-10a+12 a^2+a-30=0 (a+6)(a-5)=0 a+6=0 or a-5=0 Answer: a=-6 or a=5 You can check these answers using @ : a/(2a-6) - 3/(a^2-6a+9) = (a-2)/(3a-9) @ -6 |