How to graph the line with slope -1 passing through the point (1, 3)?


Hi the slope-intercept line looks like

y = mx+b

Since slope is -1, we know that m=-1:

y= (-1)x+b

Let's find b by plugging in (1,3) for (x,y)

y=(-1)x+b

3=-1(1)+b

3=-1+b

b=4

Thus plugging b=4 into y=(-1)x+b we get:

y=(-1)x+4

y=-x+4

Answer:

y=-x+4

Here we graph the line y=-x+4 and (1,3) in the calculator

y=-x+4; (1,3)

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