How to graph the line with slope -1 passing through the point (1, 3)? |
Hi the slope-intercept line looks like y = mx+b Since slope is -1, we know that m=-1: y= (-1)x+b Let's find b by plugging in (1,3) for (x,y) y=(-1)x+b 3=-1(1)+b 3=-1+b b=4 Thus plugging b=4 into y=(-1)x+b we get: y=(-1)x+4 y=-x+4 Answer: y=-x+4 Here we graph the line y=-x+4 and (1,3) in the calculator y=-x+4; (1,3) |